How to find the occurrences of any word with more than two vowels in a file using regex

Question

I'm having trouble figuring out how to find all words that have 2 or more vowels in them. So far this is what I have but when i run it, it don't give me any output. I appreciate the help.

import re

def main():

in_f = open("jobs-061505.txt", "r")
read = in_f.read()
in_f.close()
for word in read:
    re.findall(r"\b[aAeEiIoOuU]*", read)
    in_f = open("twoVoweledWordList.txt", "w")
    in_f.write(word)
    in_f.close()

print (word)
main()

Answer 1

for word in read:  <--- iterating over chars in "read"!
    re.findall(r"\b[aAeEiIoOuU]*", read)  <-- using read again, discarding result

your iteration and pattern usage do not align. Plus, you don't use the result.

Consider processing the file line by line etc.

twovowels=re.compile(r".*[aeiou].*[aeiou].*", re.I)
nonword=re.compile(r"\W+", re.U)
file = open("filename")
for line in file:
    for word in nonword.split(line):
        if twovowels.match(word): print word
file.close()