How to get request string without GET arguments

Question

Is there a simple way to get the requested file or directory without the GET arguments? For example, if the URL is http://example.com/directory/file.php?paramater=value I would like to return just http://example.com/directory/file.php. I was surprised that there is not a simple index in $_SERVER[]. Did I miss one?

Answer 1

Hello @kartik,

You can use $_SERVER['REQUEST_URI'] to get requested path. Then, you'll need to remove the parameters...

$uri_parts = explode('?', $_SERVER['REQUEST_URI'], 2);

Then, add in the hostname and protocol.

echo 'http://' . $_SERVER['HTTP_HOST'] . $uri_parts[0];

Hope it helps!!
Thank You!!