Cant decode hex sting into decimal Getting TypeError

Question

I am trying to decode a lenghty hex string into a decimal value. I have tried online decoders for this. Now i want to use python to decode it. I have written the code but it shows TypeError. What have i done wrong?

hex string: 0x00000000000000000000000000000000000000000000000bf97e2a21966df7fe

expected decoded result: 220892037897060743166

error:
"0x00000000000000000000000000000000000000000000000bf97e2a21966df7fe".decode("hex")

TypeError                                 Traceback (most recent call last)
<ipython-input-32-1cf86ff46cbc> in <module>()
      9 key=keyarr[0]
     10
---> 11 "0x00000000000000000000000000000000000000000000000bf97e2a21966df7fe".decode("hex")

/usr/local/Cellar/python/2.7.13_1/Frameworks/Python.framework/Versions/2.7/lib/python2.7/encodings/hex_codec.py in hex_decode(input, errors)
     40     """
     41     assert errors == 'strict'
---> 42     output = binascii.a2b_hex(input)
     43     return (output, len(input))
     44

TypeError: Non-hexadecimal digit found

I am not understanding where i went wrong. Please help me out

Answer 1

On the line where it shows error, you have used .decode("hex"). It means you are treating the string as hex data.
To get the proper result call int with a base 16, like this: int(your_string, base=16)

Output using python 3.6.1:

>>> a = '0x00000000000000000000000000000000000000000000000bf97e2a21966df7fe'
>>> a
'0x00000000000000000000000000000000000000000000000bf97e2a21966df7fe'
>>> int(a, 16)
220892037897060743166