How Can I log a Python error with debug information

Question

I am printing Python exception messages to a log file with logging.error:

import logging
try:
    1/0
except ZeroDivisionError as e:
    logging.error(e)  # ERROR:root:division by zero

Is it possible to print more detailed information about the exception and the code that generated it than just the exception string? 

Answer 1

Hii,

Using exc_info options may be better, to allow you to choose the error level (if you use exception, it will always be at the error level):

try:
    # do something here
except Exception as e:
    logging.critical(e, exc_info=True) 

Hope this works!!