Is it possible to build unbreakable Protocol Obfuscation

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With protocol obfuscation, is it theoretically possible to create an unbreakable system that can’t be reverse-engineered or detected? What are the challenges in achieving this?
Jan 10 in Cyber Security & Ethical Hacking by Anupam
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1 answer to this question.

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Achieving unbreakable protocol obfuscation—where a system is entirely impervious to reverse engineering or detection—is theoretically challenging and, in many cases, considered impossible. While obfuscation can enhance security by making protocols harder to analyze, it cannot guarantee absolute protection.

Theoretical Possibility

In cryptography, the concept of indistinguishability obfuscation (iO) has been proposed as a potential means to obfuscate programs such that their functionality remains intact while concealing their internal structure. This approach aims to make it computationally infeasible to deduce the original program from its obfuscated version. However, achieving iO for all programs is still an open problem, and current constructions are limited to specific classes of functions.

Challenges in Achieving Unbreakable Obfuscation

  1. Impossibility Results: Research has demonstrated that certain forms of obfuscation are impossible. For instance, black-box obfuscation, which aims to make a program's internal workings indistinguishable from its input-output behavior, has been proven to be unachievable in general.

  2. Performance Overhead: Implementing obfuscation techniques often introduces performance penalties, which can be detrimental in performance-critical applications.

  3. Evolving Attack Techniques: As obfuscation methods advance, so do the techniques used by attackers. Determined adversaries may develop new methods to analyze and reverse-engineer obfuscated protocols, potentially compromising their security.

  4. Complexity of Implementation: Designing and implementing effective obfuscation schemes is complex and requires a deep understanding of both the protocol's functionality and potential attack vectors.

answered Jan 10 by CaLLmeDaDDY
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