What does the C standard state the size of int long type to be

I'm seeking for specific information on the sizes of basic C++ types.

I understand that it is determined by the architecture (16 bits, 32 bits, or 64 bits) and the compiler.
But are there any C++ standards?

On a 32-bit architecture, I'm using Visual Studio 2008.

This is what I get:

char  : 1 byte
short : 2 bytes
int   : 4 bytes
long  : 4 bytes
float : 4 bytes
double: 8 bytes

I looked for solid information on the sizes of char, short, int, long, double, float (and other types I didn't think of) under different architectures and compilers, but had little luck.

Jul 5, 2022 in C++ by Nicholas
• 7,760 points • 400 views

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What does the C++ standard state the size of int, long type to be?

I'm seeking for specific information on the sizes of basic C++ types. I understand that it is determined by the architecture (16 bits, 32 bits, or 64 bits) and the compiler. But are there any C++ standards? On a 32-bit architecture, I'm using Visual Studio 2008. This is what I get: char : 1 byte short : 2 ...READ MORE

Jul 7, 2022 in C++ by Nicholas
• 7,760 points • 351 views

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What is the difference between cout, cerr, clog of iostream header in c++? When to use which one?

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Jul 27, 2022 in C++ by Nicholas
• 7,760 points • 718 views

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Tokenization is essential in determining what a programme does. What Bjarne is referring to in respect to C++ code is how tokenization rules alter the meaning of a programme. We need to know what the tokens are and how they are determined. Specifically, how can we recognise a single token when it comes among other characters, and how should tokens be delimited if there is ambiguity? Consider the prefix operators ++ and +, for example. Assume we have just one token + to deal with. What does the following excerpt mean? int i = 1; ++i; Is the above going to apply unary + on i twice with + only? Or will it only increase it once? Naturally, it's vague. We require an additional token, thus ++ is introduced as its own "word" in the language. But there is now another (though minor) issue. What if the programmer just wants to use unary + twice without incrementing? Rules for token processing are required. So, if we discover that a white space is always used as a token separator, our programmer may write: int i ...READ MORE

answered Aug 2, 2022 in C++ by Damon
• 4,960 points • 952 views

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Jun 1, 2022 in C++ by Nicholas
• 7,760 points • 518 views

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The ordered and unordered map containers (std::map and std::unordered map) are included in the standard library. The items in an ordered map are sorted by key, and insert and access are in O (log n). For ordered maps, the standard library often use red black trees. However, this is only an implementation detail. Insert and access are in O in an unordered map (1). It is simply another term for a hashtable. An illustration using (ordered) std::map: #include <map> #include <iostream> #include <cassert> int main(int argc, char ...READ MORE

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Jul 11, 2022 in C++ by Nicholas
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Foo(int num): bar(num) In C++, this is known as a Member Initializer List. Simply put, it sets the value of your member bar to num. There is a significant difference between initializing a member with the Member initializer list and assigning a value to it within the function Object() { [native code] } body. When you use the Member initializer list to initialise fields, the constructors are only called once, and the object is constructed and initialised in a single operation. If you use assignment, the fields will be initialised with default constructors and then reassigned with actual values (via the assignment operator). As you can see, there is an extra overhead of creation and assignment in the latter, which may be significant for user defined classes. Cost of Member Initialization =Object ...READ MORE