Is there a better way to run a command N times in bash

Question

I occasionally run a bash command line like this:

n=0; while [[ $n -lt 10 ]]; do some_command; n=$((n+1)); done

To run some_command a number of times in a row -- 10 times in this case.

Often some_command is really a chain of commands or a pipeline.

Is there a more concise way to do this?

Answer 1

In the event that your reach has a variable, use seq, similar to this:

count=10
for I in $(seq $count); do
    order
done
Basically:

for run in {1..10}; do
  order
done
Or on the other hand as a joke, for those that need to reorder without any problem:

for run in {1..10}; do order; done650
650

On the off chance that your reach has a variable, use seq, similar to this:

count=10
for I in $(seq $count); do
    order
done
Essentially:

for run in {1..10}; do
  order
done
Or on the other hand as a joke, for those that need to reorder without any problem:

for run in {1..10}; do order; done
On the off chance that your reach has a variable, use seq, similar to this:

count=10
for I in $(seq $count); do
    order
done
Essentially:

for run in {1..10}; do
  order
done
Or on the other hand as a joke, for those that need to reorder without any problem:

for run in {1..10}; do order; done