ln Natural Log in Python

Question

I need to create a python script to solve this equation.

 

The code I have written so far is:

import math
p = 100
r = 0.06 / 12
FV = 4000

n = str(ln * ((1 + (FV * r) / p) / (ln * (1 + r))))

print ("Number of periods = " + str(n))

The answer I should get is 36.55539635919235. Can someone help me with this? 

Answer 1

Use math.log it is a natural logarithm. For more info: https://docs.python.org/2/library/math.html.

Rewrite your equation as:

n = math.log((1 + (FV * r) / p) / math.log(1 + r)))

I hope this helps.